Validation in Java

Validations:

1. If word contains consecutive characters

String userWord = "Pankaj";
Pattern pattern = Pattern.compile("(\\w)\\1{2,}");
Matcher matcher = pattern.matcher(userWord);
if (matcher.find()) {
System.out.println("Found value is: " + matcher.group(0));
return true;
} else {
System.out.println("NO MATCH");
return false;
}

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2. If word contains more instance of characters

String userWord = "Pankaj";
Pattern pattern = Pattern.compile("(\\w)(\\w*\\1){4}");
Matcher matcher = pattern.matcher(userWord);
if (matcher.find()) {
System.out.println("Found value is: " + matcher.group(0));
return true;
} else {
System.out.println("NO MATCH");
return false;
}

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3. If word contains any name

String firstName = "Pankaj";
String emailAddress = "pankaj.lilhare@gmail.com";
// Here I want to check first name is exist on given emailAddress.

return (firstName.toUpperCase().matches("(.*)"+emailAddress.toUpperCase()+"(.*)")) ? true :false;

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4. To check name should not contains Consecutive special characters like - _ . and space

Pattern pattern = Pattern.compile("[-_. ][-_. ]");

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5. To check name should not start with special characters

Pattern pattern = Pattern.compile("^[?<>~!@#$%^&()`,.{}|;:*'\\[\\]\\-_=+\"\\/\\\\ ]");

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6. To check name should not ends with special characters

Pattern pattern = Pattern.compile("[?<>~!@#$%^&()`,.{}|;:*'\\[\\]\\-_=+\"\\/\\\\ ]$");

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For passsword validation (?!.*([A-Za-z0-9@!#$%^&*(){}?;:,./<>])\1{2})((?=.*\d)|(?=.*[@!#$%^&*(){}?;:,./<> ]))(?=.*[a-z])(?=.*[A-Z]).{8,}